Since this is anonymous, why did you REALLY redshirt your kid?

[Anonymous]

Because I could afford it. What's the point of being rich if you're not going to give your kid every advantage possible?

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

This is why I am suspicious of anyone in real life who says they are against redshirting. There is a whole lot of crazy going on with anti-redshirters.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Hi, Natural Law Lady! I have mentioned you in some “Kooks of DCUM” threads and everyone always wants a link, so thanks for making it easy.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Also, I really want to know what you think acceptable intervals are. You are clearly against classrooms having over a 12 month age span. Why are you stopping there? Why not insist on a six month age span, or three month? What is so important about 12 months exactly? Is it tied to the earth’s revolution around the sun? If so, are leap years upsetting?

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Hi, Natural Law Lady! I have mentioned you in some “Kooks of DCUM” threads and everyone always wants a link, so thanks for making it easy.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Also, I really want to know what you think acceptable intervals are. You are clearly against classrooms having over a 12 month age span. Why are you stopping there? Why not insist on a six month age span, or three month? What is so important about 12 months exactly? Is it tied to the earth’s revolution around the sun? If so, are leap years upsetting?

Oooh. Can you link the Kooks of DCUM thread?

And yes natural law antiredshirter is definitely one of the DCUM kooks.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

This is why I am suspicious of anyone in real life who says they are against redshirting. There is a whole lot of crazy going on with anti-redshirters.

You send your kids on time so they can be appropriately challenged and if they need more help, they get the help. Holding back a year, withholds a year of services and help as usually those parents holding back are in denial and not getting their kids outside help.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

Swing and a miss. There’s a reason teachers suggest giving the gift of time and it’s not because they want badly behaved older kids in class. Try again.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

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Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

Um, no. A child's behavior gets better as they get older, not worse.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

The bold isn't true. The older kids are usually enrolled in more difficult classes. They're usually the ones taking all honors and AP classes, as well os the ones who take Algebra in 7th grade and Calculus in 11th grade.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Good Lord. Have you literally never been to a high school graduation? It’s alphabetical, you loon.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

Exactly. My DD and niece are a long apart, both summer babies. I sent my DD my sister held my niece. I love her to death, but there’s a reason they didn’t send her on time. Sounds bad, but the truth is, she’s way behind my DD. I’m glad did them they have the option to hold her back vs. like a Spring birthday!!

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

Swing and a miss. There’s a reason teachers suggest giving the gift of time and it’s not because they want badly behaved older kids in class. Try again.

There is no such thing as a gift of time. You cannot get time where it doesn't exist. You cannot extend childhood and what happens is you have an adult still in high school for another year. Then you take away a year of them being an adult so you can have your child for an extra year.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

Exactly. My DD and niece are a long apart, both summer babies. I sent my DD my sister held my niece. I love her to death, but there’s a reason they didn’t send her on time. Sounds bad, but the truth is, she’s way behind my DD. I’m glad did them they have the option to hold her back vs. like a Spring birthday!!

* a month apart. Typo

[Anonymous]

Anonymous wrote:Because he was severely speech delayed, the principal recommended we “give him the gift of time “. He was 10 days short of cutoff. I truly believe they would have wanted him to repeat kindergarten or first grade

This is silly. My child had a very severe speech disorder. Of course some pushed us to hold back but it wasn't to help the child, it was to make it easier on the school so they didn't have to deal with it. They couldn't be bothered providing appropriate support or therapy. Years later I am so glad I didn't listen as speech caught up, child is very bright and in the grade they should be. Even child cannot imagine being held back as they already are in all advanced classes.