Since this is anonymous, why did you REALLY redshirt your kid?

[Anonymous]

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Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

The bold isn't true. The older kids are usually enrolled in more difficult classes. They're usually the ones taking all honors and AP classes, as well os the ones who take Algebra in 7th grade and Calculus in 11th grade.

If you are putting a held back child into Algebra in 7th, they aren't any smarter, they are older. So, if they were smart, they would have been doing it in 6th or in 7th as an age appropriate student. In our school system smart kids take Algebra in 6th or 7th grade. Mine started Algebra in 6th. You cannot brag how smart your kid is if you held them back so they are 13 in 7th vs.12 and doing Algebra. They would be doing great if they weren't held back and doing Algebra in 7th. But, held back, they really should at least be in Geometry, if not Algebra 2.

And, no, its not the older kids in more difficult classes. Its the kids with high IQ's or willing to work hard. Age does not matter as much as IQ/smarts.

[Anonymous]

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Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

Swing and a miss. There’s a reason teachers suggest giving the gift of time and it’s not because they want badly behaved older kids in class. Try again.

There is no such thing as a gift of time. You cannot get time where it doesn't exist. You cannot extend childhood and what happens is you have an adult still in high school for another year. Then you take away a year of them being an adult so you can have your child for an extra year.

Oh well. You do you, why are you so worried about others?

[Anonymous]

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Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

So your claim is that older kids simultaneously get all As and are badly behaved? That’s… interesting.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

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Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

The bold isn't true. The older kids are usually enrolled in more difficult classes. They're usually the ones taking all honors and AP classes, as well os the ones who take Algebra in 7th grade and Calculus in 11th grade.

If you are putting a held back child into Algebra in 7th, they aren't any smarter, they are older. So, if they were smart, they would have been doing it in 6th or in 7th as an age appropriate student. In our school system smart kids take Algebra in 6th or 7th grade. Mine started Algebra in 6th. You cannot brag how smart your kid is if you held them back so they are 13 in 7th vs.12 and doing Algebra. They would be doing great if they weren't held back and doing Algebra in 7th. But, held back, they really should at least be in Geometry, if not Algebra 2.

That's what I was saying. A 13-year-old 7th grader with average intelligence would be taking Algebra, while a 17-year-old 11th grader with average intelligence would be taking Calculus.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

The bold isn't true. The older kids are usually enrolled in more difficult classes. They're usually the ones taking all honors and AP classes, as well os the ones who take Algebra in 7th grade and Calculus in 11th grade.

If you are putting a held back child into Algebra in 7th, they aren't any smarter, they are older. So, if they were smart, they would have been doing it in 6th or in 7th as an age appropriate student. In our school system smart kids take Algebra in 6th or 7th grade. Mine started Algebra in 6th. You cannot brag how smart your kid is if you held them back so they are 13 in 7th vs.12 and doing Algebra. They would be doing great if they weren't held back and doing Algebra in 7th. But, held back, they really should at least be in Geometry, if not Algebra 2.

That's what I was saying. A 13-year-old 7th grader with average intelligence would be taking Algebra, while a 17-year-old 11th grader with average intelligence would be taking Calculus.

No, that's not correct. A child should be 12 going into 7th, not 13. My child in 7th would turn 12 and stay 12 in 7th. They don't turn 13 till 8th grade. A 7th grader who is smarter, will take Algebra in 7th. Average intelligence takes it in 8th or 9th grade (or if they are in private). If a child is 13/14, in 7th they either have a fall birthday or were held back. So, its not brag worthy if they were held back.

Many of our younger kid are on the fast track at school. I don't know why people are acting like it cannot be done.

Starting in 6th is impressive, especially for a young for the grade child. If you redshirt and your child does Algebra in 7th, its really the equivalent of starting in 8th and while they are smart, its really not brag worthy as that is a regular pace that they could have been on not held back.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

Swing and a miss. There’s a reason teachers suggest giving the gift of time and it’s not because they want badly behaved older kids in class. Try again.

There is no such thing as a gift of time. You cannot get time where it doesn't exist. You cannot extend childhood and what happens is you have an adult still in high school for another year. Then you take away a year of them being an adult so you can have your child for an extra year.

Oh well. You do you, why are you so worried about others?

I couldn't care less but I get tired of the age issue impacting my young for the grade child. The best gift I gave my child was to send them on time and will be to fully pay for college and graduate school. If I have money to burn, instead of an extra year of preschool, a year of graduate school makes far more sense.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

This is why I am suspicious of anyone in real life who says they are against redshirting. There is a whole lot of crazy going on with anti-redshirters.

You send your kids on time so they can be appropriately challenged and if they need more help, they get the help. Holding back a year, withholds a year of services and help as usually those parents holding back are in denial and not getting their kids outside help.

I did not redshirt. I do, however, think that DCUM anti redshirt posters are absolute nutcases, weirder than any other group on DCUM.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

Exactly. My DD and niece are a long apart, both summer babies. I sent my DD my sister held my niece. I love her to death, but there’s a reason they didn’t send her on time. Sounds bad, but the truth is, she’s way behind my DD. I’m glad did them they have the option to hold her back vs. like a Spring birthday!!

You seem like an awful aunt. I feel for your niece.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

This is why I am suspicious of anyone in real life who says they are against redshirting. There is a whole lot of crazy going on with anti-redshirters.

You send your kids on time so they can be appropriately challenged and if they need more help, they get the help. Holding back a year, withholds a year of services and help as usually those parents holding back are in denial and not getting their kids outside help.

I did not redshirt. I do, however, think that DCUM anti redshirt posters are absolute nutcases, weirder than any other group on DCUM.

I think its really sad that people KNOW their kids are delayed instead of getting them help or even putting the in a better preschool, they just delay things for a year and hope it all works out.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

This is why I am suspicious of anyone in real life who says they are against redshirting. There is a whole lot of crazy going on with anti-redshirters.

You send your kids on time so they can be appropriately challenged and if they need more help, they get the help. Holding back a year, withholds a year of services and help as usually those parents holding back are in denial and not getting their kids outside help.

I did not redshirt. I do, however, think that DCUM anti redshirt posters are absolute nutcases, weirder than any other group on DCUM.

I think its really sad that people KNOW their kids are delayed instead of getting them help or even putting the in a better preschool, they just delay things for a year and hope it all works out.

But it does all work out. Redshirting turns would-be-struggling students into okay students and would-be-okay students into stellar students.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

Swing and a miss. There’s a reason teachers suggest giving the gift of time and it’s not because they want badly behaved older kids in class. Try again.

There is no such thing as a gift of time. You cannot get time where it doesn't exist. You cannot extend childhood and what happens is you have an adult still in high school for another year. Then you take away a year of them being an adult so you can have your child for an extra year.

Oh well. You do you, why are you so worried about others?

I couldn't care less but I get tired of the age issue impacting my young for the grade child. The best gift I gave my child was to send them on time and will be to fully pay for college and graduate school. If I have money to burn, instead of an extra year of preschool, a year of graduate school makes far more sense.

So they’re negatively impacted by being the youngest, and yet being the youngest is the best gift you gave them? Okay then!

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

So your claim is that older kids simultaneously get all As and are badly behaved? That’s… interesting.

DCUM antiredshirters aren't really known for their rigorous logic.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

Swing and a miss. There’s a reason teachers suggest giving the gift of time and it’s not because they want badly behaved older kids in class. Try again.

There is no such thing as a gift of time. You cannot get time where it doesn't exist. You cannot extend childhood and what happens is you have an adult still in high school for another year. Then you take away a year of them being an adult so you can have your child for an extra year.

Oh well. You do you, why are you so worried about others?

I couldn't care less but I get tired of the age issue impacting my young for the grade child. The best gift I gave my child was to send them on time and will be to fully pay for college and graduate school. If I have money to burn, instead of an extra year of preschool, a year of graduate school makes far more sense.

So they’re negatively impacted by being the youngest, and yet being the youngest is the best gift you gave them? Okay then!

Ah, ha. So the anti redshirting poster has finally revealed why she feels the way she does. And then how she’s making herself feel better about it. Her kid isn’t the smartest in the classroom, but she’s making herself feel better by construing what she did as a gift to him, and herself as a good parent for following the “rules” the “natural law”. Thanks for letting us know,but I still think you should just love your kid for where they’re at, and remember that everyone is struggling with something. Smug parents are the worst whether their kids are old or young. Just avoid them and lay this sh*t down. You’re ok. Your kid is ok. See you in a few years on the DCUM college forum, and I hope you’re not there railing about college acceptances!

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Do you think that for the graduation ceremony, everyone should line up by birthdates so the oldest get their diplomas first? That way the natural law will be satisfied.

Well, that probably already happens. Students usually get their diplomas in their order of class rank. Since older students do better, the order of class rank is going to be the same as the order of age.

Usually its the not so smart kids that the parents try to make smart by holding them back. They are older, not smarter. It gives everyone a false sense of identity as if you hold your kids back and don't put them in advanced classes, you can scream they are so smart for all A's when they are only doing it as they are older and in dumbed down classes.

We all know who the older kids are. You usually know because of their behavior, which isn't good.

Swing and a miss. There’s a reason teachers suggest giving the gift of time and it’s not because they want badly behaved older kids in class. Try again.

There is no such thing as a gift of time. You cannot get time where it doesn't exist. You cannot extend childhood and what happens is you have an adult still in high school for another year. Then you take away a year of them being an adult so you can have your child for an extra year.

Oh well. You do you, why are you so worried about others?

I couldn't care less but I get tired of the age issue impacting my young for the grade child. The best gift I gave my child was to send them on time and will be to fully pay for college and graduate school. If I have money to burn, instead of an extra year of preschool, a year of graduate school makes far more sense.

So they’re negatively impacted by being the youngest, and yet being the youngest is the best gift you gave them? Okay then!

Ah, ha. So the anti redshirting poster has finally revealed why she feels the way she does. And then how she’s making herself feel better about it. Her kid isn’t the smartest in the classroom, but she’s making herself feel better by construing what she did as a gift to him, and herself as a good parent for following the “rules” the “natural law”. Thanks for letting us know,but I still think you should just love your kid for where they’re at, and remember that everyone is struggling with something. Smug parents are the worst whether their kids are old or young. Just avoid them and lay this sh*t down. You’re ok. Your kid is ok. See you in a few years on the DCUM college forum, and I hope you’re not there railing about college acceptances!

She couldn't care less but then goes on to tell you why she's wildly insecure about her kid's progress in school because he's a few months younger than others. She didn't have enough money for more preschool but she assumes if one did they also wouldn't have a child go to graduate school. It's either/or but not both in delusional land. She's a green eyed monster who thinks she made the wrong choice and is trying to come to terms with it. Maybe focus more on the issues your own child is having in school and less on the birthday calendar.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

This is why I am suspicious of anyone in real life who says they are against redshirting. There is a whole lot of crazy going on with anti-redshirters.

You send your kids on time so they can be appropriately challenged and if they need more help, they get the help. Holding back a year, withholds a year of services and help as usually those parents holding back are in denial and not getting their kids outside help.

I did not redshirt. I do, however, think that DCUM anti redshirt posters are absolute nutcases, weirder than any other group on DCUM.

I think its really sad that people KNOW their kids are delayed instead of getting them help or even putting the in a better preschool, they just delay things for a year and hope it all works out.

The alternative seems to be sending them on time and then blaming the older kids when issues crop up instead of getting the child the help they needed in the first place. But, it can't be that, it has to be the older kids negatively impacting the younger.