Since this is anonymous, why did you REALLY redshirt your kid?

[Anonymous]

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

[Anonymous]

I understand that some 5 year olds are not ready for Kindergarten at the “right” time. But couldn’t there be different tiers of kindergarten so that the very youngest and/or developmentally delayed could be given instruction that from where they are at.

The social element of sitting next to kids who are your own age is important so that coming of age milestone can be celebrated together. For example, my friendship group used to have birthdays in the same month and at 13 we planned a cinema trip to see a PG13 movie one our youngest friends birthday.

[Anonymous]

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

TL DR. It's clear as mud because you are too long winded. I have 2 kids with Sept and November birthdays who are the correct age given cut offs. What's all this chatter about October birthdays being so old? You are so freaking weird.

[Anonymous]

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

[Anonymous]

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

This does nothing to defend your point. I'm a teacher, by the way. Chronological age isn't everything.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

What's all this chatter about October birthdays being so old?

Well, they're usually in the youngest quarter of their class, but a redshirted kid with an October birthday would cause the problems I pointed out.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

[Anonymous]

So now we can assume that the crazy anti-red-shirt-poster is a math person.

And she's mad because her kid sucks at math, or didn't get into a magnet program or something, or is painfully average at math.

Keep poster, anti-red shirt lady - we're going to figure out who you are pretty soon!

hahahahaha

[Anonymous]

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

As said above, you lack capacity and need pity, not engagement.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

[Anonymous]

Anonymous wrote:Because kids who are older almost alway do better. This is especially true in college. I don't know anyone who was redshirted who dropped out of college or took longer than 4 years to graduate. I bet that if you looked at everyone who ever dropped out of college, you'd see that the vast majority started college before they turned 18.

Wow. That is not even remotely close to true. Way to demonstrate that you live in a bubble where people go directly from HS to college, PP.

[Anonymous]

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:

Anonymous wrote:Why are you trying to demonstrate facts with someone who has repeatedly shown that she is incapable of basic understanding? It is like arguing with a rock. This is the natural law antiredshirter. She lacks capacity. You can point out the facts of the academic year until you are blue in the face, and she will not comprehend. She needs compassion and serious help outside of DCUM. What she doesn't need is to be taken seriously.

Let me see if I can explain why redshirting and greenshirting are problematic with a few examples

Let's suppose that in a given school district, you decide to line up all the students in that district in order of their ages on a huge field, with the oldest on the left end and the youngest on the right end. Let's also suppose that you have 13 long ropes and that you want to use each rope to encircle all the students in a certain year by laying the rope along the grass around them. The rope on the left end would be placed around the feet of the 12th graders, while the rope on the right end would be placed around the feet of the Kindergarteners. In order for this to be able to work, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. For instance, let's suppose you have a redshirted 11th grader with an early October birthday. This means they would be standing to the left of roughly a quarter of the 12th graders. It would be impossible to encircle all the 12th graders without also encircling the redshirted 11th grader, and it would also be impossible to encircle all the 11th graders without also encircling the quarter of 12th graders younger than the redshirted 11th grader.

For another example, let's suppose that you print a list of the names of all the students in a given school district in order of age, with the name of the oldest on the top and the name of the youngest on the bottom. Let's suppose that you want to cut that list up such that you have one sheet for each grade. In order to be able to do this, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. In this case, you would simply make each cut between the name of the youngest student in grade N and the name of the oldest student in grade N-1. But let's suppose there's a greenshirted 12th grader with an early April birthday. This means their name would be listed below roughly a quarter of the 11th grader's names. Making the first cut right above the name of the oldest 11th grader would leave out that 12th grader, but making the first cut right below the name of the greenshirted 12th grader would include that oldest quarter of 11th graders. In other words, you'd be quite torn about where to make that first cut.

For a final example, let's suppose you record the exact ages of all the students in a given school district. Afterwards, you decide to make 13 disjoint closed intervals to represent each grade, where the lower bound represents the age of the youngest student in that grade and the upper bound represents the age of the oldest student in that grade. For those who don't know, two intervals are disjoint when their intersection is empty. For instance, the intervals [2, 3] and [4, 5] are disjoint because the upper boundary of one interval is less than the lower boundary of the other interval. However, the intervals [2, 4] and [3, 5] are not disjoint because their intersection is [3, 4], which obviously isn't empty. In order for all 13 intervals to be disjoint with each other, the youngest student in any given year(aside from Kindergarten) would have to be older than the oldest student in the year below. Let's suppose that the interval for 11th graders is [Q, R] and that the interval for 12th graders is [S, T]. As long as R<S, then the intervals will be disjoint. However, if there's a redshirted 11th grader with an early October birthday, then that pretty much guarantees that R>S, as R will reflect the age of the redshirted 11th grader, and S will reflect the age of someone who had turned 17 that month. In that case, the intersection would be [S, R], which obviously isn't empty.

I hope it's now crystal clear why I'm against redshirting and greenshirting.

Seek. Help.

Also TL;DR but good grief! +1!

Well, you really only need to read one of the paragraphs to get the idea. I just really wanted to drive home my point.

Well, you failed again. Unless your point is to prove that you are bonkers. In that case, good job!

I just thought of a much more simple way to explain what I'm getting at. You know how it defies nature to die someone older than you, right? Well, it also defies nature to graduate high school before someone older than you.

Whatever weirdo. I have a May birthday, a lot of people were older than me at HS graduation. I'm doing quite well in life, I guess I defied nature. What do you think HS graduation should look like? Should you be kicked out the day you turn 17? Can kids never skip a grade? You're like a hammer looking for a nail with your "solution" to a "problem" that doesn't actually exist. HS graduation age isn't really a big deal in the grand scheme of life.

[Anonymous]

Because he was severely speech delayed, the principal recommended we “give him the gift of time “. He was 10 days short of cutoff. I truly believe they would have wanted him to repeat kindergarten or first grade